Ta có : \(x=2+\sqrt{3}\Rightarrow x-2=\sqrt{3}\Leftrightarrow x^2-4x+4=3\Leftrightarrow x^2-4x+1=0\)
Mặt khác \(x=2+\sqrt{3}\Rightarrow2x-5=2\sqrt{3}-1\)
Khi đó \(A=\frac{\left(x^2-4x+1\right)\left(x^2+2x+10\right)+2x-5}{\sqrt{x^2-4x+1+4}}=\frac{2\sqrt{3}-1}{2}=\sqrt{3}-\frac{1}{2}\)