Question

Tính 

a/ \(A=17\frac{2}{31}-\left(\frac{15}{17}+6\frac{2}{31}\right)\)

b/ \(B=\left(31\frac{6}{13}+5\frac{9}{41}\right)-36\frac{6}{13}\)

c/ \(C=27\frac{51}{59}-\left(7\frac{51}{59}-\frac{1}{3}\right)\)

d/ \(D=\left(13\frac{29}{31}-3\frac{7}{8}\right)-\left(2\frac{28}{31}-4\right)\)

Answer 1

\(A=17\frac{2}{31}-\left(\frac{15}{17}+6\frac{2}{31}\right)=\left(17\frac{2}{31}-6\frac{2}{31}\right)-\frac{15}{17}=11-\frac{15}{17}=10+\left(1-\frac{15}{17}\right)=10\frac{2}{17}\)

Answer 2

\(B=\left(31\frac{6}{13}-36\frac{6}{13}\right)+5\frac{9}{41}=-5+5\frac{9}{41}=\frac{9}{41}\)

C=\(\left(27\frac{51}{59}-7\frac{51}{59}\right)+\frac{1}{3}=20+\frac{1}{3}=20\frac{1}{3}\)

\(D=\left(13\frac{29}{31}-2\frac{28}{31}\right)+\left(4-3\frac{7}{8}\right)=11\frac{1}{31}+\frac{1}{8}=11\frac{8+31}{31.8}=11\frac{39}{248}\)