\(\left[{}\begin{matrix}\left(2x-1\right)^2=0\\\left(y-2\right)^2=0\\\left(z-3\right)^2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x-1=0\\y-2=0\\z-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0,5\\y=2\\z=3\end{matrix}\right.\)
a,\(\left|3x-4\right|+\left|3y+5\right|=0\) b,\(\left|x+\dfrac{19}{5}\right|+\left|y+\dfrac{1890}{1975}\right|+\left|z-2004\right|=0\) c,\(\left|x+\dfrac{9}{2}\right|+\left|y+\dfrac{4}{3}\right|+\left|z+\dfrac{7}{2}\right|\le0\)
d,\(\left|x+\dfrac{3}{4}\right|+\left|y-\dfrac{1}{5}\right|+\left|x+y+z\right|=0\) e,\(\left|x+\dfrac{3}{4}\right|+\left|y-\dfrac{2}{5}\right|+\left|z+\dfrac{1}{2}\right|\le0\)
Giups mình giải bài tìm x,y,z này nhé!!! Cảm ơn nhiều ạ!!!
Tìm x,y,z biết: \(\left|x-\frac{1}{2}\right|+\left|y+\frac{2}{3}\right|+\left|x^2+xz\right|=0\)
Tìm x,y,z trong các tỉ lệ thức sau: \(3.\left(x-1\right)=2.\left(y-2\right);4.\left(y-2\right)=3.\left(z-3\right)v\text{à}2x+3y-z=50\)
Tìm \(x\in Z,y\in Z\):
a) \(x^2+y^2=2\)
b) \(\left(x-3\right)^2+\left(2y-1\right)^2=1\)
c) \(\left|2x-1\right|+\left|y+5\right|=0\)
\(2\left|2x-6\right|=\dfrac{5}{6}-\left|x-3\right|\)
2:\(\left|x+2013\right|+\left|x+2014\right|+\left|x+2045\right|=2\)
3:\(\left|2x-1\right|=\left|x+1\right|\)
4:\(\sqrt{\left(x+\sqrt{5}\right)}+\sqrt{\left(y-\sqrt{3}\right)^2}+\left|x-y-z\right|=0\)
Tìm x,y,z trong các tỉ lệ thức sau: \(3.\left(x-1\right)=2.\left(y-2\right);4.\left(y-2\right)=3.\left(z-3\right)v\text{à}2x+3y-z=50\)
Tìm x,y,z biết
\(\left(2x-1\right)^{2008}+\left(y-\frac{2}{5}\right)^{2008}+\left|x+y-z\right|=0\)
Tìm x, y, z, biết:
\(3\left(x-1\right)=2\left(y-2\right)\);
\(4\left(y-2\right)=3\left(z-3\right)\);
\(2x+3y-z=50\)
Cho \(2\left(x-3\right)=3\left(y+2\right);5\left(2-z\right)=3\left(y+z\right)\)và \(2x-3y+z=-4\). Tìm giá trị của \(B=x-y+z\)
