\(2x^2+3y^2=77\Rightarrow2\left(x^2+y^2\right)+y^2=77\)
Vì 2( x2 + y2 ) chẵn ; 77 lẻ
=> y2 lẻ (1)
Ta có : \(y^2\ge0\forall y\Rightarrow0\le y^2\le77\)
Kết hợp (1) => y2 \(\in\left\{1;9;25;49\right\}\)
=> y \(\in\left\{1;3;5;7\right\}\)
........ (you can continue)