Question

tìm x,y biét:(x-0,5)^2010+|x+y+0,5|=0

Answer 1

+ \(\left\{{}\begin{matrix}\left(x-0,5\right)^{2010}\ge0\forall x\\\left|x+y+0,5\right|\ge0\forall x,y\end{matrix}\right.\)

\(\Rightarrow\left(x-0,5\right)^{2010}+\left|x+y+0,5\right|\ge0\forall x,y\)

Dấu "=" xảy ra \(\Leftrightarrow\left\{{}\begin{matrix}\left(x-0,5\right)^{2010}=0\\\left|x+y+0,5\right|=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=0,5\\y=-1\end{matrix}\right.\)