\(x^2-7x+10=0\)
\(\Leftrightarrow x^2-2x-5x+10=0\)
\(\Leftrightarrow x\left(x-2\right)-5\left(x-2\right)=0\)
\(\Leftrightarrow\left(x-2\right)\left(x-5\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x-2=0\\x-5=0\end{array}\right.\) \(\Leftrightarrow\left[\begin{array}{nghiempt}x=2\\x=5\end{array}\right.\)
x2 -7x + 10 = 0
=> x2 - 2x - 5x + 10 = 0
=> x(x - 2) - 5(x - 2) = 0
=> (x - 5)(x - 2) = 0
=> x-5=0;x=5
x-2=0;x=2
Vậy x = 2 hoặc x = 5