x2 -7x + 10 = 0
=> x2 - 2x - 5x + 10 = 0
=> x(x - 2) - 5(x - 2) = 0
=> (x - 5)(x - 2) = 0
=> \(\left[\begin{array}{nghiempt}x-5=0\\x-2=0\end{array}\right.\) => \(\left[\begin{array}{nghiempt}x=5\\x=2\end{array}\right.\)
Vậy x = 2 hoặc x = 5
x2 - 7x + 10 = 0
=> x2 - 2x - 5x + 10 = 0
=> ( x2 - 2x ) - ( 5x - 10 ) = 0
=> x( x - 2 ) - 5( x - 2 ) = 0
=> ( x - 2 ) . ( x - 5 ) = 0
Ta có: x - 2 = 0
=> x = 2
hoặc x - 5 = 0
=> x = 5
Vậy x = 2 hoặc x = 5
x2 - 7x + 10 = 0
\(\Rightarrow\) (x - \(\frac{7}{2}\))2 - \(\frac{9}{4}\) = 0
\(\Rightarrow\) (x - \(\frac{7}{2}\))2 = \(\frac{9}{4}\)
\(\Rightarrow\) x - \(\frac{7}{2}\) = \(\frac{3}{2}\)
\(\Rightarrow\) x = 5
