a: \(\Leftrightarrow10\left|x-2\right|=50\)
=>|x-2|=5
\(\Leftrightarrow\left[{}\begin{matrix}x-2=5\\x-2=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=7\\x=-3\end{matrix}\right.\)
b: \(\Leftrightarrow x-2+x+3-\left(3x-5\right)=4\)
\(\Leftrightarrow2x+1-3x+5=4\)
=>6-x=4
hay x=2(loại)