a: \(\Leftrightarrow x\cdot\dfrac{-6}{5}+\dfrac{3}{5}-x^2+\dfrac{1}{2}x-\dfrac{1}{6}+x^2=0\)
\(\Leftrightarrow x\cdot\dfrac{-7}{10}=-\dfrac{13}{30}\)
hay \(x=\dfrac{13}{21}\)
b: \(\Leftrightarrow x\cdot\dfrac{1}{4}=1-\dfrac{26}{3}=\dfrac{-23}{3}\)
hay x=-23/12
c: =>3|x-1/2|=8
=>|x-1/2|=8/3
=>x-1/2=8/3 hoặc x-1/2=-8/3
=>x=19/6 hoặc x=-13/6