Question

tìm x
4-x=2.(x-4)^2

 

Answer 1

Answer 2

\(4-x=2\left(x-4\right)^2\)

\(\Leftrightarrow2\left(x-4\right)^2+x-4=0\)

\(\Leftrightarrow\left(x-4\right)\left(2x-7\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=\dfrac{7}{2}\end{matrix}\right.\)

Answer 3

\(4-x=2\left(x-4\right)^2\)

\(\Leftrightarrow2\left(x-4\right)^2+x-4=0\)

\(\Leftrightarrow\left(x-4\right)\left(2x-7\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=\dfrac{7}{2}\end{matrix}\right.\)

Answer 4

4 - x = 2(x - 4)²

<=> -(4 - x) = \(-\left[2\left(x-4\right)^2\right]\)

<=> -1 = \(-\left[2\left(x-4\right)\right]\)

<=> -1 = -2x + 8

<=> 2x = 8 + 1

<=> x = \(\dfrac{9}{2}\)