1: \(\Leftrightarrow x\cdot\dfrac{8}{x}=1\cdot\dfrac{1}{2}\)
=>8=1/2(loại)
2: =>16x=15x
=>x=0
3: =>7x+7=9x-9
=>-2x=-16
=>x=8
1: \(\Leftrightarrow x\cdot\dfrac{8}{x}=1\cdot\dfrac{1}{2}\)
=>8=1/2(loại)
2: =>16x=15x
=>x=0
3: =>7x+7=9x-9
=>-2x=-16
=>x=8
Tìm x:
1) \(\dfrac{1,2}{30}\)\(=\dfrac{3x+4}{50}\)
2) \(\dfrac{x-1}{x-5}\)\(=\dfrac{6}{7}\)
3) \(\dfrac{x-1}{3}\)\(=\dfrac{x+3}{5}\)
4) \(\dfrac{3}{7}\)\(=\dfrac{2x+1}{3x+5}\)
5) \(\dfrac{2x+3}{3x+1}\)\(=\dfrac{3}{4}\)
6) \(\dfrac{2x+3}{6}\)\(=\dfrac{7x-3}{15}\)
7) \(\dfrac{6x-5}{-7}\)\(=\dfrac{5x-3}{-5}\)
8) \(\dfrac{x+1}{x-2}\)\(=\dfrac{3}{4}\)
9) \(\dfrac{2x-3}{x+1}\)\(=\dfrac{4}{7}\)
10) \(\dfrac{2x+3}{7}\)\(=\dfrac{4x-1}{15}\)
11) \(\dfrac{2x+3}{24}\)\(=\dfrac{3x-1}{32}\)
12) \(\dfrac{2x+4}{7}\)\(=\dfrac{4x-2}{15}\)
13) \(\dfrac{11x-2}{7x+5}\)\(=\dfrac{11}{8}\)
14) \(\dfrac{12-7x}{-13}\)\(=\dfrac{4-3x}{-5}\)
15) \(\dfrac{52}{2x-1}\)\(=\dfrac{13}{30}\)
Tìm x, biết :
\(a.3\dfrac{4}{5}:40\dfrac{8}{15}=0,25:x\)
\(b.\left(x+1\right):\dfrac{5}{6}=20:3\)
\(c.\dfrac{7}{x-1}=\dfrac{x+1}{9}\)
bài tìm x,y,z biết :a)\(\dfrac{x}{5}=\dfrac{y}{6};\dfrac{y}{8}=\dfrac{z}{7}\)và x+y-z=69
b)\(\dfrac{x}{3}=\dfrac{y}{4};\dfrac{y}{3}=\dfrac{z}{5}\)và 2x-3y+z=6
c)\(\dfrac{x}{2}=\dfrac{y}{5}=\dfrac{z}{6}\)và x+y=14
d)\(\dfrac{2}{3x}=\dfrac{1}{2y}=\dfrac{2}{z}\)và 3x+2y+z=1
1,2x :\(\dfrac{5}{7}\)=\(\dfrac{14}{15}\) : \(\dfrac{3}{2}\)
2,\(\dfrac{9}{10}\) :(3x) = \(\dfrac{5}{3}:\dfrac{20}{27}\)
3,\(\dfrac{x-2}{27}=\dfrac{3}{x-2}\)
4,\(\dfrac{2x+5}{9-2x}=\dfrac{2}{5}\)
5,\(\dfrac{x-7}{x+8}=\dfrac{x-8}{x+9}\)
Tìm hai số x,y biết
a/\(\dfrac{x^3}{8}=\dfrac{y^3}{27}=\dfrac{z^3}{64};x^2+2y^2-3z^2=-650\)
b/\(\dfrac{x-1}{2}=\dfrac{y+3}{4}=\dfrac{z-5}{6};5z-3x-4y=50\)
Tìm x trong tỉ lệ thức
a) \(-0,52:x=-9,36:16,38\)
b) \(2\dfrac{2}{5}:x=1\dfrac{7}{9}:0,2\)
c)\(\left(\dfrac{2}{5}x\right):\dfrac{1}{3}=1\dfrac{1}{3}:\dfrac{4}{5}\)
d) \(0,3:1\dfrac{1}{3}=\dfrac{2}{5}:\left(3x+6\right)\)
e) \(\dfrac{x}{-15}=\dfrac{-60}{x}\)
f) \(\dfrac{x-1}{-15}=\dfrac{-60}{x-1}\)
g) \(\dfrac{x-1}{7}=\dfrac{9}{x+1}\)
h) \(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}\)
Tìm x,y biết: \(\dfrac{x+3}{6} = \dfrac{2x + 1 }{7} = \dfrac{2 + 3x}{y}\)
1) \(\dfrac{-5}{\dfrac{12}{\left|\dfrac{2}{3}x+\dfrac{1}{2}\right|}}\)= \(\dfrac{\dfrac{-4}{9}}{\dfrac{8}{15}}\)
2) \(\dfrac{\left|3x-5\right|}{-3}\)= \(\dfrac{\dfrac{-5}{6}}{\dfrac{4}{9}}\)
bài 1 : tì tỉ lệ thức \(\dfrac{a}{b} = \dfrac{c}{d}\) hãy suy ra
a, \(\dfrac{a}{a+b}\) = \(\dfrac{c}{c+d}\)
b, \(\dfrac{a}{a-b}=\dfrac{c}{c-d}\)
bài 2 : lập tỉ lệ thức có được từ các số sau
a, 3;4; 4 và 1 phần 2 ;5;6
b, 3;4;15;20
bài 3 : tìm x biết
a, \(\dfrac{x}{0,9}=\dfrac{5}{6}\)
b, \(\dfrac{14}{15}: \dfrac{9}{10}= x:\dfrac{3}{7}\)
c, \(\dfrac{-6}{x} = \dfrac{9}{-15}\)
d, 1 và 3 phần 5 chia 8 = 2,5 : x
e, \(\dfrac{x}{2}=\dfrac{8}{x}\)
g, \(\dfrac{3x-7}{8}=\dfrac{5}{2}\)
dạng : tỉ lệ thức
tìm x biết
a, \(\dfrac{x-2}{-1,2}=\dfrac{-5}{2}\)
b, \(\dfrac{-6}{x+1}=\dfrac{1,8}{9}\)
c, \(\dfrac{-3}{x}=\dfrac{x}{-12}\)
d, \(\dfrac{x-4}{x-1}=\dfrac{3}{5}\)
e,\(\dfrac{1,12}{-10}=\dfrac{11,2}{x}\)