Question

TIM X

Answer 1

\(\dfrac{1}{16^x}=\dfrac{1}{32^{16}}\Rightarrow16^x=32^{16}\Rightarrow2^{4x}=2^{80}\Rightarrow4x=80\Rightarrow x=20\)

Answer 2

Ta có: \(\left(\dfrac{1}{16}\right)^x=\left(\dfrac{1}{32}\right)^{16}\)

\(\Leftrightarrow\left(\dfrac{1}{2}\right)^{4x}=\left(\dfrac{1}{2}\right)^{80}\)

\(\Leftrightarrow4x=80\)

hay x=20