\(x-\dfrac{4}{3}=\dfrac{x+2}{-2}\)
\(\Rightarrow x-\dfrac{4}{3}=\dfrac{-x}{2}-1\)
\(\Rightarrow x+\dfrac{1}{2}x=\dfrac{4}{3}-1\)
\(\Rightarrow\dfrac{3}{2}x=\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{2}{9}\)
Vậy \(x=\dfrac{2}{9}.\)
\(x-\dfrac{4}{3}=\dfrac{x+2}{-2}\)
\(\Rightarrow x-\dfrac{4}{3}=\dfrac{-x}{2}-1\)
\(\Rightarrow x+\dfrac{1}{2}x=\dfrac{4}{3}-1\)
\(\Rightarrow\dfrac{3}{2}x=\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{2}{9}\)
Vậy \(x=\dfrac{2}{9}.\)
tim x biet: ||x-1/2|.|2x-3/4||=2x-3/4
|(x+1/2).|2x-3/4||=2x-3/4 tim x biet
Tim x biet :
\(a,\frac{x-1}{2009}+\frac{x-2}{2008}=\frac{x-3}{2007}+\frac{x-4}{2006}\)
\(b,\left|x-1\right|+\left|x-2\right|+\left|x-3\right|=4\left(x-4\right)\)
Tim x biet
x/1/2= -3/4/5/8
Giup milk vs
Thanks truoc
tim x biet \(x-2\sqrt{x}=0\)
tim x biet \((x^2-20)\times\left(x^2-15\right)\left(x^2-10\right)\left(x^2-5\right)< 0\)
tim x biet \(\left|x-5\right|< =2\)
Tim x:\(\dfrac{x}{y}=\dfrac{1}{3}\)
Biet : \(x-\dfrac{3}{y}=\dfrac{1}{2}\)
Ai lam truoc mk se tick nha!
Tim x biet: -10x3 + x + 3 = 0