Question

tìm x ,y

a) \(1\frac{1}{3}x-\frac{1}{4}=\frac{5}{6}\)

b) /x-\(\frac{\frac{1}{2}}{ }\)-\(\sqrt{\frac{1}{9}}=\sqrt{\frac{1}{4}}\)

c) (x+20)¹⁰⁰+/y+4/=0

Answer 1

a: \(\Leftrightarrow x\cdot\dfrac{4}{3}=\dfrac{5}{6}+\dfrac{1}{4}=\dfrac{13}{12}\)

\(\Leftrightarrow x=\dfrac{13}{12}:\dfrac{4}{3}=\dfrac{13}{12}\cdot\dfrac{3}{4}=\dfrac{39}{48}=\dfrac{13}{16}\)

b: \(\Leftrightarrow\left|x-\dfrac{1}{2}\right|=\dfrac{1}{2}+\dfrac{1}{3}=\dfrac{5}{6}\)

=>x-1/2=5/6 hoặc x-1/2=-5/6

=>x=4/3 hoặc x=-1/3

c: \(\left(x+20\right)^{100}+\left|y+4\right|=0\)

=>x+20=0 và y+4=0

=>x=-20 và y=-4