Ta có \(\frac{1+2y}{18}\)=\(\frac{1+4y}{24}\)
\(\Rightarrow\)(1+2y)24=(1+4y)18
\(\Rightarrow\)24+48y=18+72y
\(\Rightarrow\)24-18=72y-48y
\(\Rightarrow\)6=24y
\(\Rightarrow\)y=\(\frac{6}{24}\)
\(\Rightarrow\)y=\(\frac{1}{4}\)
Thay y=\(\frac{1}{4}\) vào đề ta có:
1 + 2\(\frac{1}{4}\) / 18 = 1 + 4\(\frac{1}{4}\) / 24 = 1 + 6\(\frac{1}{4}\) / 6x
=>\(\frac{1}{12}\)=\(\frac{\frac{5}{2}}{\frac{6}{x}}\)
=>12.\(\frac{5}{2}\)=6x
=>30=6x
=>x=5
Vậy x=5;y=\(\frac{1}{4}\)
ta co : 1+2y/18=1+4y/24
=> 24(1+2y)=18(1+4y)
=>24+48y=18+72y
=>24-18=72y-48y
=>6=24y
=>y=1/4
thay y thanh 1/4 vao de bai ta co :
1+1/2/18=1+1/24=(1+3/2)/6x
=>1/12=(5/2)/6x
=>12/(5/2)=6x
=>30=6x/x=5
vay x=5 va y=1/4
Ta có 1+2y181+2y18=1+4y241+4y24
⇒⇒(1+2y)24=(1+4y)18
⇒⇒24+48y=18+72y
⇒⇒24-18=72y-48y
⇒⇒6=24y
⇒⇒y=624624
⇒⇒y=1414
Thay y=1414 vào đề ta có:
1 + 21414 / 18 = 1 + 41414 / 24 = 1 + 61414 / 6x
=>112112=526x526x
=>12.5252=6x
=>30=6x
=>x=5
Vậy x=5;y=14