Vì xy = -3
=> \(x;y\inƯ\left(-3\right)\)
mà Ư ( -3 ) = { -3 ; -1; 1; 3 }
Nếu x = -3 ; y = 1
Nếu x = -1; y = 3
Nếu x = 1 ; y = -3
Nếu x = 3 ; y =-1
Vậy x = 1; y =-3
x = 3; y = -1
x= -1; y = 3
x = -3 ; y =1
Vì xy = -3
=> \(x;y\inƯ\left(-3\right)\)
mà Ư ( -3 ) = { -3 ; -1; 1; 3 }
Nếu x = -3 ; y = 1
Nếu x = -1; y = 3
Nếu x = 1 ; y = -3
Nếu x = 3 ; y =-1
Vậy x = 1; y =-3
x = 3; y = -1
x= -1; y = 3
x = -3 ; y =1
Tim x, y biet:
x- a/m = y- b/n va x+y=k
Tim x:\(\dfrac{x}{y}=\dfrac{1}{3}\)
Biet : \(x-\dfrac{3}{y}=\dfrac{1}{2}\)
Ai lam truoc mk se tick nha!
Tim x biet: -10x3 + x + 3 = 0
Tim cac so x, y, z biet : 2x-2 .3y-3 .5z-1 =144.
Xin loi vi khong viet dau duoc, cac ban co gang giup me lam nhanh nhe, me dang can gap
tim x biet: ||x-1/2|.|2x-3/4||=2x-3/4
|(x+1/2).|2x-3/4||=2x-3/4 tim x biet
Tim x biet
x-4/3=x+2/-2
tim 2 so x va y biet
a, \(\frac{x}{3}\)=\(\frac{y}{7}\) va x+y=20
b, \(\frac{x}{5}\)=\(\frac{y}{2}\)vax-y=6
1)Tim he so a cua da thuc A(x)=-7x2-3y2 +9xy-2x2+y2,biet rang da thuc co1 nghiem bang\(\dfrac{1}{2}\)
2) Tim m, biet rang da thuc Q(x)=mx2 + 2mx -3co 1 nghiemx=-1