ta có : \(\left(x^2+1\right)\left(x-2\right)+2x=4\Leftrightarrow\left(x^2+1\right)\left(x-2\right)+2x-4=0\)
\(\Leftrightarrow\left(x^2+1\right)\left(x-2\right)+2\left(x-2\right)=0\Leftrightarrow\left(x^2+3\right)\left(x-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x^2+3=0\\x-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x\in\varnothing\\x=2\end{matrix}\right.\) vậy \(x=2\)
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