x2 - 10x = -25
x2 - 2 . x . 5 + 52 = 0
(x - 5)2 = 0
x - 5 = 0
x = 5
x2 - 12x = -36
x2 - 2 . x . 6 + 62 = 0
(x - 6)2 = 0
x - 6 = 0
x = 6
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\(x^2-10x=-25\)
\(\Rightarrow x^2-10x+25=0\)
\(\Rightarrow x^2-2.5.x+5^2=0\)
\(\Rightarrow\left(x-5\right)^2=0\)
\(\Rightarrow x-5=0\)
\(\Rightarrow x=5\)
Vậy \(x=5\)
\(x^2-12x=-36\)
\(\Rightarrow x^2-12x+36=0\)
\(\Rightarrow x^2-2.6.x+6^2=0\)
\(\Rightarrow\left(x-6\right)^2=0\)
\(\Rightarrow x-6=0\)
\(\Rightarrow x=6\)