\(\left(x-2\right).\left(x+4\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x-2=0\\x+4=0\end{array}\right.\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=2\\x=-4\end{array}\right.\)
Vậy \(x\in\left\{2;-4\right\}\)
(x - 2) (x + 4) = 0
=> x - 2 = 0 hoặc x + 4 = 0
=> x = 2 hoặc x = -4
( x - 2 ).( x+4 ) = 0
\(\Rightarrow\) x - 2 = 0 hoặc x + 4 = 0
+) x - 2 = 0
x = 0 + 2
x = 2
+) x + 4 = 0
x = 0 - 4
x = -4
Vậy x = 2 hoặc x = -4
(x-2).(x+4)=0
x-2=0 x=0+2 x= 2
x+4=0 x =0-4 x= -4
\(\left(x-2\right).\left(x+4\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}\left(x-2\right)=0\\\left(x+4\right)=0\end{array}\right.\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0+4\\x=0-4\end{array}\right.\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=2\\x=-4\end{array}\right.\)
Vậy: \(\left[\begin{array}{nghiempt}x=2\\x=-4\end{array}\right.\)