Question

tìm x thuộc Q biết

(x-2/3)(x+1/4)=0

Answer 1

\(\left(x-\dfrac{2}{3}\right)\left(x+\dfrac{1}{4}\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x-\dfrac{2}{3}=0\\x+\dfrac{1}{4}=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=\dfrac{-1}{4}\end{matrix}\right.\)

Answer 2

\(\left(x-\dfrac{2}{3}\right)\left(x+\dfrac{1}{4}\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x-\dfrac{2}{3}=0\\x+\dfrac{1}{4}=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=\dfrac{-1}{4}\end{matrix}\right.\)

Answer 3

\(\left(x-\dfrac{2}{3}\right)\left(x+\dfrac{1}{4}\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{2}{3}=0\\x+\dfrac{1}{4}=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=\dfrac{-1}{4}\end{matrix}\right.\)

Vậy \(x=\dfrac{2}{3}\) hoặc \(x=-\dfrac{1}{4}\)