\(\left(x+1\right)^2=\frac{4}{9}\) = + \(\frac{2}{3}\)
\(\Rightarrow\left[\begin{array}{nghiempt}x+1=\frac{2}{3}\\x+1=-\frac{2}{3}\end{array}\right.\) \(\Rightarrow\left[\begin{array}{nghiempt}x=-\frac{1}{3}\\x=-\frac{5}{3}\end{array}\right.\)
\(\left(x+1\right)^2=\frac{4}{9}\Rightarrow\left[\begin{array}{nghiempt}x+1=\frac{2}{3}\\x+1=-\frac{2}{3}\end{cases}\Rightarrow\left[\begin{array}{nghiempt}x=-\frac{1}{3}\\x=-\frac{5}{3}\end{array}\right.}\)
\(\left(x+1\right)^2=\frac{4}{9}\)
\(\left(x+1\right)^2=\left(\pm\frac{2}{3}\right)^2\)
\(x+1=\pm\frac{2}{3}\)
TH1:
\(x+1=\frac{2}{3}\)
\(x=\frac{2}{3}-1\)
\(x=-\frac{1}{3}\)
TH2:
\(x+1=-\frac{2}{3}\)
\(x=-\frac{2}{3}-1\)
\(x=-\frac{5}{3}\)
Vậy x = -1/3 hoặc x = -5/3
(x+1)2=4/9
=>(x+1)2=(2/3)2
x+1=2/3
=> x=-1/3
