( 2x - 1 )2 + ( x + 3)2 - 5 ( x + 7 )( x - 7 ) = 0
⇔ ( 4x2 - 4x + 1 ) + ( x2 + 6x + 9 ) - 5 ( x2 - 49 ) = 0
⇔ 4x2 - 4x + 1 + x2 + 6x + 9 - 5x2 + 245 = 0
⇔ 2x + 255 = 0 ⇔ 2x = - 255 ⇔ x = - 127,5
Vậy ...
Tìm x, biết:
a. \(\left(2x-3\right)^2-4=0\)
b.\(x^2-2x=0\)
c.\(\left(2x-1\right)^2+\left(x+3\right)^2-5\left(x+7\right)\left(x-7\right)=0\)
Bài 1: Cm giá trị của biểu thức sau không phụ thuộc vào biến x:
a) \(\left(2x+3\right).\left(4x^2-6x+9\right)-2\left(4x^3-1\right)\)
b)\(\left(x+3\right)^3+\left(x+9\right).\left(x^2+27\right)\)
c)\(\left(x+y\right).\left(x^2-xy+y^2\right)+\left(x-y\right).\left(x^2+xy+y^2\right)-2x^3\)
Bài 2: Tìm x biết:
a) \(\left(x+2\right)^2-9=0\)
b) \(\left(x+2\right)^2-x^2+4=0\)
c) \(\left(x-3\right)^2-4=0\)
d) \(x^2-2x=24\)
e) \(\left(2x-1\right)^2+\left(x+3\right)^2-5\left(x-7\right)\left(x+7\right)=0\)
tìm x biết
a) \(\left(2x-1\right)^2+\left(x+3\right)^2-5\left(x+7\right)\left(x-7\right)=24\)
b) \(\left(x+3\right)^2-\left(x-4\right)\left(x-8\right)=1\)
Tìm x thỏa mãn đẳng thức cho trước
a) \(\left(x+2\right).\left(x^2-4x+4\right)-\left(x^3+2x^2\right)=5\)
b) \(6x^2-6x.\left(-2+x\right)=36\)
c) \(\left(x+2\right)^2+\left(x-3\right)^2-2.\left(x-1\right).\left(x+1\right)=9\)
d) (\(\left(x+5\right)^2-9=0\)
e) \(\left(x-2\right)^3=x^3+6x^2=7\)
\(\left(2x-1\right)^2+\left(x+3\right)^2-5x.\left(x+7\right).\left(x-7\right)\)
1) \(27+\left(x-3\right).\left(x^2+3x+9\right)=-x\)
2) \(-4\left(x+2\right)-7\left(2x-1\right)+9\left(4-3x\right)=30\)
3) \(x^2-4x+4=0\)
4) \(\left(x-1\right).\left(x^2+x+1\right)-x.\left(x+2\right).\left(x-2\right)=5\)
Tìm x giúp mk vs nha mai mk đi hk rùi
giải pt
a.\(\dfrac{3x-1}{x-1}-\dfrac{2x+5}{x+3}=1-\dfrac{4}{\left(x-1\right)\left(x+3\right)}\)
b. \(\dfrac{13}{\left(x-3\right)\left(2x+7\right)}+\dfrac{1}{2x+7}=\dfrac{6}{\left(x-3\right)\left(x+3\right)}\)
tìm x biết
a)\(\left(x-2\right)^2-x\left(x+1\right)\left(x-1\right)+6x\left(x-3\right)=0\)
b)\(\left(x-2\right)\left(x^2-2x+4\right)\left(x+2\right)\left(x^2+2x+4\right)-x^6+2x=1\)
c)\(\left(x-3\right)\left(x^2+3x+9\right)+x\left(x+2\right)\left(2-x\right)=1\)
Bài 3: Tìm x biết:
1, \(4x^2-36=0\)
2, \(\left(x-1\right)^2+x\left(4-x\right)=11\)
3, \(\left(x-5\right)^2-x.\left(x+2\right)=5\)
4, \(x\left(x+4\right)-x^2-6x=10\)
