Chương I : Số hữu tỉ. Số thực
Các câu hỏi tương tự
Bài 1 : Tìm \(x,y,z\in Q\)
\(a)\left|x-3,5\right|+\left|4,5-y\right|=0\)
\(b)\left|x-2\right|+\left|3-y\right|=0\)
\(c)\left|x+\frac{2}{3}\right|+\left|y-\frac{3}{4}\right|+\left|z-5\right|=0\)
\(d)\left|x+\frac{13}{14}\right|+\left|x-\frac{3}{7}\right|=0\)
giúp mình với ❤❤❤
Tìm x, y, z:
a) left|x+dfrac{19}{5}right|+left|y+dfrac{1890}{1975}right|+left|z-2005right|0
b) left|x+dfrac{3}{4}right|+left|y-dfrac{1}{5}right|+left|x+y+zright| 0
c) dfrac{16}{2^x}1
d) left(2x-1right)^3-27
e) left(x-2right)^21
f) left(x+dfrac{1}{2}right)^2dfrac{4}{25}
g) left(x-1right)^2left(x-1right)^6
Đọc tiếp
Tìm x, y, z:
a) \(\left|x+\dfrac{19}{5}\right|+\left|y+\dfrac{1890}{1975}\right|+\left|z-2005\right|=0\)
b) \(\left|x+\dfrac{3}{4}\right|+\left|y-\dfrac{1}{5}\right|+\left|x+y+z\right|\) = 0
c) \(\dfrac{16}{2^x}=1\)
d) \(\left(2x-1\right)^3=-27\)
e) \(\left(x-2\right)^2=1\)
f) \(\left(x+\dfrac{1}{2}\right)^2=\dfrac{4}{25}\)
g) \(\left(x-1\right)^2=\left(x-1\right)^6\)
Tìm x,biết
a, frac{3}{left(x+2right)left(x+5right)}+frac{5}{left(x+5right)left(x+10right)}+frac{7}{left(x+10right)left(x+17right)}frac{x}{left(x+2right)left(x+17right)}
Với x ∉ -2,-5,-10,-17
b,frac{2}{left(x-1right)left(x-3right)}+frac{5}{left(x-3right)left(x-8right)}+frac{12}{left(x-8right)left(x-20right)}-frac{1}{x-20}frac{-3}{4}
Với x∉1,3,8,20
c,frac{x-1}{2009}+frac{x-2}{2008}frac{x-3}{2007}+frac{x-4}{2006}
Đọc tiếp
Tìm x,biết
a, \(\frac{3}{\left(x+2\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(x+10\right)}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\)
Với x ∉ -2,-5,-10,-17
b,\(\frac{2}{\left(x-1\right)\left(x-3\right)}+\frac{5}{\left(x-3\right)\left(x-8\right)}+\frac{12}{\left(x-8\right)\left(x-20\right)}-\frac{1}{x-20}=\frac{-3}{4}\)
Với x∉1,3,8,20
c,\(\frac{x-1}{2009}+\frac{x-2}{2008}=\frac{x-3}{2007}+\frac{x-4}{2006}\)
Chứng minh nếu dfrac{a}{b} dfrac{c}{d} thì:
dfrac{a+c}{b+d}dfrac{a-c}{b-d}
Tìm
a. Min A 3 left|2x+1right|-4
b. min B dfrac{3}{left|xright|-2}(x ϵ Z)
c. max A dfrac{1}{2left(x-2right)^2+2}
d. max B dfrac{x+1}{left|xright|}left(xin Zright)
Đọc tiếp
Chứng minh nếu \(\dfrac{a}{b}\)= \(\dfrac{c}{d}\) thì:
\(\dfrac{a+c}{b+d}=\dfrac{a-c}{b-d}\)
Tìm
a. Min A = 3 \(\left|2x+1\right|\)-4
b. min B = \(\dfrac{3}{\left|x\right|-2}\)(x ϵ Z)
c. max A = \(\dfrac{1}{2\left(x-2\right)^2+2}\)
d. max B = \(\dfrac{x+1}{\left|x\right|}\left(x\in Z\right)\)
a.Tìm x, y, z biết \(\frac{x}{3}=\frac{y}{4};\frac{y}{5}=\frac{z}{7}\) và 2x+3y-z=186
b. Tìm các số a, b, c, d. Biết a:b:c:d=2:3:4:5 và 3a+b-2c+4d=105
c. Timd x, y, z biết \(\left(2x-3\right)^2+\left|2y+3\right|+\left|1-z\right|=0\)
tìm x;y
b left|x-yright|+left|y+dfrac{9}{25}0right|
c left(dfrac{1}{2}x-5right)^{20}+left(y^2-dfrac{1}{4}right)^{10}0
a left|dfrac{1}{2}-dfrac{1}{3}+xright|dfrac{-1}{4}-y
d left|xleft(x^2-dfrac{5}{4}right)right|x left(xge0right)
e x^2+left(y-dfrac{1}{10}right)^40
Đọc tiếp
tìm x;y
b \(\left|x-y\right|+\left|y+\dfrac{9}{25}=0\right|\)
c \(\left(\dfrac{1}{2}x-5\right)^{20}+\left(y^2-\dfrac{1}{4}\right)^{10}=0\)
a \(\left|\dfrac{1}{2}-\dfrac{1}{3}+x\right|=\dfrac{-1}{4}-y\)
d \(\left|x\left(x^2-\dfrac{5}{4}\right)\right|=x\) \(\left(x\ge0\right)\)
e \(x^2+\left(y-\dfrac{1}{10}\right)^4=0\)
Tìm x, biết:
a) left(x-frac{-7}{8}right)+2,33,24 ; b) x.left(4,6+frac{3}{5}right)7,2-8,15 ; c) |2x-3|+316 ; d) 42+frac{3}{7}.left|3x-1right|12
e) left(x-frac{1}{2}right).left(1+5xright)0 ; f) |2x-1||x+2| ; g) 2.3^x.3^218left(xin Nright) ; h) frac{x+2}{5}frac{2-3x}{3}
Đọc tiếp
Tìm x, biết:
a) \(\left(x-\frac{-7}{8}\right)+2,3=3,24\) ; b) \(x.\left(4,6+\frac{3}{5}\right)=7,2-8,15\) ; c) |2x-3|+3=16 ; d) \(42+\frac{3}{7}.\left|3x-1\right|=12\)
e) \(\left(x-\frac{1}{2}\right).\left(1+5x\right)=0\) ; f) |2x-1|=|x+2| ; g) \(2.3^x.3^2=18\left(x\in N\right)\) ; h) \(\frac{x+2}{5}=\frac{2-3x}{3}\)
tìm x biết:
a) \(\left(x-2\right)^2+\left(y-3\right)^2=0\)
b) \(5^{\left(x-2\right).\left(x+3\right)}=1\)
c) \(-\left(-x-y\right)^2=\left(yz-3\right)^2\)
Tìm x, biết:
a) \(\left(\frac{-3}{4}\right)^{3x-1}=\frac{-27}{64}\)
b) \(\left(\frac{4}{5}\right)^{2x+5}=\frac{256}{265}\)
c) \(\frac{\left(x+3\right)^5}{\left(x+3\right)^2}=\frac{64}{27}\)
d) \(\left(x-\frac{2}{15}\right)^3=\frac{8}{125}\)