\(\frac{x+2}{5}=\frac{1}{x-2}\)
\(\Leftrightarrow\left(x+2\right).\left(x-2\right)=5\)
\(\Leftrightarrow x.\left(x-2\right)+2.\left(x-2\right)=5\)
\(\Leftrightarrow x^2-2x+2x-4=5\)
\(\Leftrightarrow x^2=5+4\)
\(\Leftrightarrow x^2=9=3^2=\left(-3\right)^2\)
\(\Rightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)
Vậy : \(x\in\left\{3,-3\right\}\)
\(\frac{x+2}{5}=\frac{1}{x-2}\)
=> \(\left(x+2\right).\left(x-2\right)=1.5\)
=> \(\left(x+2\right).\left(x-2\right)=5\)
=> \(x^2-2x+2x-4=5\)
=> \(x^2=5+4\)
=> \(x^2=9\)
=> \(\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)
Vậy \(x\in\left\{3;-3\right\}.\)
Chúc bạn học tốt!
Tìm x:
x+2/5=1/x−2
=> (x+2)(x-2)=5.1
=> x^2-2^2=5
=> x^2=1
=> x=\(\sqrt{1}\)
