Câu hỏi của Lâm Ánh Yên

Question

Tìm x: $\dfrac{x^2-4}{x+2}=\dfrac{3x}{2}$

Nguyễn Thanh Hằng · Accepted Answer

$\dfrac{x^2-4}{x+2}=\dfrac{3x}{2}$

$\Leftrightarrow\dfrac{\left(x-2\right)\left(x+2\right)}{x+2}=\dfrac{3x}{2}$

$\Leftrightarrow x-2=\dfrac{3x}{2}$

$\Leftrightarrow3x=\left(x-2\right)2$

$\Leftrightarrow3x=2x-4$

$\Leftrightarrow3x-2x=-4$

$\Leftrightarrow x=-4$

Vậy..Câu trả lời: $\dfrac{x^2-4}{x+2}=\dfrac{3x}{2}$

$\Leftrightarrow\dfrac{\left(x-2\right)\left(x+2\right)}{x+2}=\dfrac{3x}{2}$

$\Leftrightarrow x-2=\dfrac{3x}{2}$

$\Leftrightarrow3x=\left(x-2\right)2$

$\Leftrightarrow3x=2x-4$

$\Leftrightarrow3x-2x=-4$

$\Leftrightarrow x=-4$

Vậy..

Sáng · Answer

$\dfrac{x^2-4}{x+2}=\dfrac{3x}{2}$

$\Leftrightarrow\dfrac{\left(x+2\right)\left(x-2\right)}{x+2}=\dfrac{3x}{2}\Leftrightarrow x-2=\dfrac{3x}{2}$

$\Leftrightarrow3x=2x-4$

$\Leftrightarrow3x-2x=-4$

$\Leftrightarrow x=-4$Câu trả lời: $\dfrac{x^2-4}{x+2}=\dfrac{3x}{2}$

$\Leftrightarrow\dfrac{\left(x+2\right)\left(x-2\right)}{x+2}=\dfrac{3x}{2}\Leftrightarrow x-2=\dfrac{3x}{2}$

$\Leftrightarrow3x=2x-4$

$\Leftrightarrow3x-2x=-4$

$\Leftrightarrow x=-4$

Violympic toán 8