Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}=\dfrac{x-2-x-4}{x-1-x-7}=\dfrac{-6}{-8}=\dfrac{3}{4}\)
Nên: \(\dfrac{x-2}{x-1}=\dfrac{3}{4}\)
\(\Leftrightarrow4x-8=3x-3\)
\(\Leftrightarrow4x-5=3x\)
\(\Leftrightarrow x=5\)
Tìm x trong tỉ lệ thức
a) \(-0,52:x=-9,36:16,38\)
b) \(2\dfrac{2}{5}:x=1\dfrac{7}{9}:0,2\)
c)\(\left(\dfrac{2}{5}x\right):\dfrac{1}{3}=1\dfrac{1}{3}:\dfrac{4}{5}\)
d) \(0,3:1\dfrac{1}{3}=\dfrac{2}{5}:\left(3x+6\right)\)
e) \(\dfrac{x}{-15}=\dfrac{-60}{x}\)
f) \(\dfrac{x-1}{-15}=\dfrac{-60}{x-1}\)
g) \(\dfrac{x-1}{7}=\dfrac{9}{x+1}\)
h) \(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}\)
\((85\dfrac{7}{30}-83\dfrac{5}{18}):2\dfrac{2}{3}=0,01x:4\)
Tim x
tim x,y,z biết
\(\dfrac{y+a+9}{x}=\dfrac{x+z+2}{y}=\dfrac{x+z-3}{z}=\dfrac{1}{x+y+z}\)
Tìm x, biết :
\(a.3\dfrac{4}{5}:40\dfrac{8}{15}=0,25:x\)
\(b.\left(x+1\right):\dfrac{5}{6}=20:3\)
\(c.\dfrac{7}{x-1}=\dfrac{x+1}{9}\)
tim x, y biet
a ,\(\dfrac{x}{2}=\dfrac{y}{5}\) va x . y = 3,6
b , \(\dfrac{x}{3}=\dfrac{y}{4}\) va x . y =108
giup minh nhe minh dang can gap
Tìm x , x biết :
a) / x - z / - / - \(\dfrac{3}{7}\) / = 10
b) / \(\left(x+\dfrac{1}{2}\right)\) / 2 x - \(\dfrac{3}{4}\) / / = 2x - \(\dfrac{3}{4}\)
c) / x / \(x^2\) + \(\dfrac{3}{4}\) // = 2x - \(\dfrac{3}{4}\)
dạng : tỉ lệ thức
tìm x biết
a, \(\dfrac{x-2}{-1,2}=\dfrac{-5}{2}\)
b, \(\dfrac{-6}{x+1}=\dfrac{1,8}{9}\)
c, \(\dfrac{-3}{x}=\dfrac{x}{-12}\)
d, \(\dfrac{x-4}{x-1}=\dfrac{3}{5}\)
e,\(\dfrac{1,12}{-10}=\dfrac{11,2}{x}\)
tim x
a, \(2,75\div x=0,4\div1,5\)
b, \(3\dfrac{1}{2}\div\left(2x-3\right)=\dfrac{-3}{4}\div0,2\)
c, \(\dfrac{3x+2}{27}=\dfrac{3}{3x+2}\)
d ,\(\dfrac{5-x}{4}=\dfrac{2x+3}{2}\)
giup minh nhe minh dang can gap
Tìm x :
c) \(\dfrac{x+4}{20}=\dfrac{5}{x+4}\) d) \(\dfrac{x-1}{x+2}=\dfrac{x-2}{x+3}\)
mọi người ơi giúp mik với , ai làm đc mik tick cho
