Tìm x, biết :
\(a.3\dfrac{4}{5}:40\dfrac{8}{15}=0,25:x\)
\(b.\left(x+1\right):\dfrac{5}{6}=20:3\)
\(c.\dfrac{7}{x-1}=\dfrac{x+1}{9}\)
tìm x,y thuộc Z biết:
a, \(\left(x+4\right)\left(y+3\right)=3\)
b,\(\left(x+2\right)\left(y-3\right)=-3\)
c,\(\dfrac{x+1}{2}=\dfrac{1}{y}\)
d, \(\dfrac{x-7}{-1}=\dfrac{13}{2-y}\)
tim x
a, \(2,75\div x=0,4\div1,5\)
b, \(3\dfrac{1}{2}\div\left(2x-3\right)=\dfrac{-3}{4}\div0,2\)
c, \(\dfrac{3x+2}{27}=\dfrac{3}{3x+2}\)
d ,\(\dfrac{5-x}{4}=\dfrac{2x+3}{2}\)
giup minh nhe minh dang can gap
Tìm các số x,y,z biết
a) \(\dfrac{x}{3}=\dfrac{y}{4}=\dfrac{z}{5}\) và \(2x+3y+5z=86\)
b) \(\dfrac{x}{3}=\dfrac{y}{4};\dfrac{y}{6}=\dfrac{z}{8}\) và \(3x-2y-z=13\)
c) \(x:y:z=2:5:7\) và \(3x+2y-z=27\)
d) \(\dfrac{x}{3}=\dfrac{y}{7}=2x^2+y^2+3z^2=316\)
câu 1 tìm A biết
\(A=\dfrac{a}{b+c}=\dfrac{c}{a+b}=\dfrac{b}{a+c}\)
câu 2
x∈Z để A∈Z
\(A=\dfrac{x+3}{x-2}\)
\(A=\dfrac{1-2x}{x+3}\)
nếu ai giải được mình cho 1 like
bài tìm x,y,z biết :a)\(\dfrac{x}{5}=\dfrac{y}{6};\dfrac{y}{8}=\dfrac{z}{7}\)và x+y-z=69
b)\(\dfrac{x}{3}=\dfrac{y}{4};\dfrac{y}{3}=\dfrac{z}{5}\)và 2x-3y+z=6
c)\(\dfrac{x}{2}=\dfrac{y}{5}=\dfrac{z}{6}\)và x+y=14
d)\(\dfrac{2}{3x}=\dfrac{1}{2y}=\dfrac{2}{z}\)và 3x+2y+z=1
dạng : tỉ lệ thức
tìm x biết
a, \(\dfrac{x-2}{-1,2}=\dfrac{-5}{2}\)
b, \(\dfrac{-6}{x+1}=\dfrac{1,8}{9}\)
c, \(\dfrac{-3}{x}=\dfrac{x}{-12}\)
d, \(\dfrac{x-4}{x-1}=\dfrac{3}{5}\)
e,\(\dfrac{1,12}{-10}=\dfrac{11,2}{x}\)
1 .Tìm x , y , z biết rằng :
\(\dfrac{2x}{3}=\dfrac{3y}{4}=\dfrac{4z}{5}\) và x + y + z = 49
2.Thực hịên phép tính :
\(2^3+3\times\left(\dfrac{1}{2}\right)^2-\dfrac{1}{2^2}+\text{[}\left(-2\right)^2:\dfrac{1}{2}\times8\)
Giúp mik vs , cần gấp lắm .
Tìm x trong tỉ lệ thức
a) \(-0,52:x=-9,36:16,38\)
b) \(2\dfrac{2}{5}:x=1\dfrac{7}{9}:0,2\)
c)\(\left(\dfrac{2}{5}x\right):\dfrac{1}{3}=1\dfrac{1}{3}:\dfrac{4}{5}\)
d) \(0,3:1\dfrac{1}{3}=\dfrac{2}{5}:\left(3x+6\right)\)
e) \(\dfrac{x}{-15}=\dfrac{-60}{x}\)
f) \(\dfrac{x-1}{-15}=\dfrac{-60}{x-1}\)
g) \(\dfrac{x-1}{7}=\dfrac{9}{x+1}\)
h) \(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}\)