\(\left(85\dfrac{7}{30}-83\dfrac{5}{18}\right):2\dfrac{2}{3}=0,01x:4\)
\(\Leftrightarrow[\left(85-83\right)+\left(\dfrac{7}{30}-\dfrac{5}{18}\right)]:2\dfrac{2}{3}=0,01x:4\)
\(\Leftrightarrow1\dfrac{43}{45}:2\dfrac{2}{3}=0,01x:4\)
\(\Leftrightarrow\dfrac{88}{45}:\dfrac{8}{3}=0,01x:4\)
\(\Leftrightarrow\dfrac{88}{45}.\dfrac{3}{8}=0,01x:4\)
\(\Leftrightarrow\dfrac{11}{15}=0,01x:4\)
\(\Leftrightarrow0,01x:4=\dfrac{11}{15}\)
\(\Leftrightarrow x=\dfrac{11}{15}.4:0,01\)
\(\Leftrightarrow x=\dfrac{880}{3}\)
Vậy x = \(\dfrac{880}{3}\)
Ta có:
\(\left(85\dfrac{7}{30}-83\dfrac{5}{18}\right):2\dfrac{2}{3}=0.01x:4\\ \left(\left(85-83\right)+\left(\dfrac{7}{30}-\dfrac{5}{18}\right)\right):\dfrac{8}{3}=0.01x:4\\ \dfrac{88}{45}:\dfrac{8}{3}=0.01x:4\\ \dfrac{11}{15}=0.01x:4\\ \dfrac{44}{15}=0.01x\\ x=\dfrac{44}{15}:0.01\\ x=\dfrac{880}{3}\)
Vậy \(x=\dfrac{880}{3}\)
