\(\dfrac{x-1}{x+2}=\dfrac{x-2}{x+3}\)
\(\Rightarrow\left(x-1\right)\left(x+3\right)=\left(x+2\right)\left(x-2\right)\)
\(\Rightarrow x^2+3x-x-3=x^2-2x+2x-4\)
\(\Rightarrow x^2+2x-3=x^2-4\)
\(\Rightarrow2x=-1\)
\(\Rightarrow x=-0,5\)
Vậy...
Ta có: \(\dfrac{x-1}{x+2}=\dfrac{x-2}{x+3}\)
\(\Rightarrow\left(x-1\right)\left(x+3\right)=\left(x+2\right)\left(x-2\right)\)
\(\Rightarrow x^2+2x-x-3=x^2-4\)
\(\Rightarrow x^2-x^2+2x-x=-4+3\)
\(\Rightarrow x=-1\)
Vậy \(x=-1\)
\(\dfrac{x-1}{x+2}=\dfrac{x-2}{x+3}\)
\(\Rightarrow\left(x-1\right)\left(x+3\right)=\left(x+2\right)\left(x-2\right)\)
\(\Rightarrow x^2+3x-x+3=x^2-2x+2x-4\)
\(\Rightarrow x^2+2x+3=x^2-4\)
\(\Rightarrow x^2+2x=x^2-7\)
\(\Rightarrow x^2-x^2+2x=7\)
\(\Rightarrow2x=7\Rightarrow x=3,5\)
Sao mỗi câu đều ra kết quả khác nhau nhưng bn đều chọn đúng cả vậy???????
