\(\left|x-2\right|-2x=-1\)
⇒ \(\left|x-2\right|=-1+2x\)
⇒ \(\left[{}\begin{matrix}x-2=-1+2x\\x-2=1-2x\end{matrix}\right.\) ⇒ \(\left[{}\begin{matrix}x-2x=\left(-1\right)+2\\x+2x=1+2\end{matrix}\right.\) ⇒ \(\left[{}\begin{matrix}-1x=1\\3x=3\end{matrix}\right.\)
⇒ \(\left[{}\begin{matrix}x=1:\left(-1\right)\\x=3:3\end{matrix}\right.\) ⇒ \(\left[{}\begin{matrix}x=-1\\x=1\end{matrix}\right.\)
Vậy \(x\in\left\{-1;1\right\}.\)
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