a) \(\left(2x-3\right)^2=1\)
\(\left(2x-3\right)^2=\left(\pm1\right)^2\)
\(\Rightarrow\begin{cases}2x-3=1\\2x-3=-1\end{cases}\)
\(\Rightarrow\begin{cases}2x=1+3\\2x=-1+3\end{cases}\)
\(\Rightarrow\begin{cases}2x=4\\2x=2\end{cases}\)
\(\Rightarrow\begin{cases}x=4:2\\x=2:2\end{cases}\)
\(\Rightarrow\begin{cases}x=2\\x=1\end{cases}\)
Vậy \(x\in\left\{2;1\right\}\)
\(\left(2x-3\right)^2=1\)
\(\Rightarrow\left(2x-3\right)^2=\left(\pm1\right)\)
\(\Rightarrow\begin{cases}2x-3=1\\2x-3=-1\end{cases}\)
\(\Rightarrow\begin{cases}2x=4\\2x=2\end{cases}\)
\(\Rightarrow\begin{cases}x=2\\x=1\end{cases}\)
Vậy : \(x\in\left\{1;2\right\}\)
\(\left(2x-3\right)^2=1\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}2x-3=1\Rightarrow x=2\\2x-3=-1\Rightarrow x=1\end{array}\right.\)
Vậy...
(2x-3)^2=1
=))(2x-3)^2=1^2 hoặc (2x-3)^2=(-1)^2
=))2x-3=1 hoặc 2x-3=-1
=))2x=4 hoặc 2x=2
=))x=2 hoặc x=1
(2x-3)^2=1^2
2x-3 =1
2x =1+3
2x =4
x =4/2
x =2
