Question

Tìm x, biết x(x - 4) - (x^2 -12) = 0

Answer 1

\(\Leftrightarrow x^2-4x-x^2+12=0\\ \Leftrightarrow-4x=-12\\ \Leftrightarrow x=3\)

Answer 2

x.( x - 4)-(x²- 12) = 0

=> x² - 4x -x²+12=0

=> -4x +12 = 0

=> -4x = -12

=> x=3

hoctot

Answer 3

x2−4x−x2+12=0

−4x=−12

x=3