\( (x-3)^2-(x+3)^2=0 \\ (x-3+x+3)(x-3-x-3)=0 \\ 2x.(-6)=0 \\ x=0 \)
\( (x-3)^2-(x+3)^2=0 \\ (x-3+x+3)(x-3-x-3)=0 \\ 2x.(-6)=0 \\ x=0 \)
Bài 1: Tìm x biết a) x^3 - 4x^2 - x + 4= 0 b) x^3 - 3x^2 + 3x + 1=0 c) x^3 + 3x^2 - 4x - 12=0 d) (x-2)^2 - 4x +8 =0
tìm x biết
(x-1)2-1+x2-(1-x)(x+3)=0
Tìm x, biết:
2(x + 3) – x2 – 3x = 0
Tìm x, biết :
a) \(x^3-\dfrac{1}{4}x=0\)
b) \(\left(2x-1\right)^2-\left(x+3\right)^2=0\)
c) \(x^2\left(x-3\right)+12-4x=0\)
tìm x biết
a/ x^3-x^2-x+1=0
b/(2x^3-3)^2-(4x^2-9)=0
c/x^4+2x^3-6x-9=0
d/2(x+5)-x^2-5x=0
tìm x biết
a/ x^3-x^2-x+1=0
b/(2x^3-3)^2-(4x^2-9)=0
c/x^4+2x^3-6x-9=0
d/2(x+5)-x^2-5x=0
tìm x, biết:
a) (3x-1)2+(x+3)3-5(2x-3)(x+3)=0
b) x2-4x+4-(x+3)(x-3)=0
c) x2-3x+2=0
Tìm x biết
x - 2 = 0
( x - 4)(x + 4) - x(x - 3) = -1
x3 - 9x = 0
5(x - 2 ) - x + 2 = 0