Ta có: \(\left|x-3\right|+\left|2x-4\right|=5\left(1\right)\)
Xét 3 TH:
\(TH1:x< 2\)
\(\left(1\right)\Leftrightarrow-\left(x-3\right)-\left(2x-4\right)=5\Leftrightarrow x=\frac{2}{3}\left(TM\right)\)
\(TH2:2\le x\le3\)
\(\left(1\right)\Leftrightarrow-\left(x-3\right)+\left(2x-4\right)=5\Leftrightarrow x=6\) (loại)
\(TH3:x>3\)
\(\left(1\right)\Leftrightarrow\left(x-3\right)+\left(2x-4\right)=5\Leftrightarrow x=4\left(TM\right)\)
Vậy \(x=4\) và \(x=\frac{2}{3}\)
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