Question

Tìm x biết : (x-1)mũ x+4 = (x-1)mũ x+2

Answer 1

các bạn làm giúp mình với ^^

Answer 2

\(\left(x-1\right)^{x+4}=\left(x-1\right)^{x+2}\)

\(\Leftrightarrow\left(x-1\right)^{x+4}-\left(x-1\right)^{x+2}=0\)

\(\Leftrightarrow\left(x-1\right)^{x+2}\left(x^2-2x\right)=0\)

\(\Leftrightarrow\left(x-1\right)^{x+2}\left(x-2\right)x=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}\left(x-1\right)^{x+2}=0\\x-2=0\\x=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=1\\x=2\\x=0\end{array}\right.\)

 

Answer 3

Ta có: \(\left(x-1\right)^{x+4}=\left(x-1\right)^{x+2}\)

\(\Rightarrow x+4=x+2\)\(\in\varnothing\)

\(\Rightarrow\) vô nghiệm

Chắc sai ak

Answer 4

Đề sai rùi! Cũng như 1 mũ 2 bằng 1 mũ 4