\(\left|x-\dfrac{1}{3}\right|+\dfrac{4}{5}=\left|\left(-3,2\right)+\dfrac{2}{5}\right|\\ \Rightarrow\left|x-\dfrac{1}{3}\right|+\dfrac{4}{5}=\left|\dfrac{-14}{5}\right|\\ \Rightarrow\left|x-\dfrac{1}{3}\right|+\dfrac{4}{5}=\dfrac{14}{5}\\ \Rightarrow\left|x-\dfrac{1}{3}\right|=2\\ \Rightarrow\left[{}\begin{matrix}x-\dfrac{1}{3}=-2\\x-\dfrac{1}{3}=2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-5}{3}\\x=\dfrac{7}{3}\end{matrix}\right.\)