\(|x-\frac{1}{3}|+\frac{4}{5}=|\left(-3,2\right)+\frac{2}{5}|\)
\(\left|x-\frac{1}{3}\right|+\frac{4}{5}=\left|\frac{-16}{5}+\frac{2}{5}\right|\)
\(\left|x-\frac{1}{3}\right|+\frac{4}{5}=\left|\frac{-14}{5}\right|\)
\(\left|x-\frac{1}{3}\right|+\frac{4}{5}=\frac{14}{5}\)
\(\Rightarrow\left|x-\frac{1}{3}\right|=\frac{14}{5}-\frac{4}{5}\)
\(\left|x-\frac{1}{3}\right|=\frac{10}{5}\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\frac{1}{3}=\frac{-10}{5}\\x-\frac{1}{3}=\frac{10}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\frac{-5}{3}\\x=\frac{7}{3}\end{matrix}\right.\)
Vậy: \(x\in\left\{\frac{-5}{3};\frac{7}{3}\right\}\)
Chúc bạn học tốt nhé !!!
∣ ∣ ∣ x − 1 3 ∣ ∣ ∣ + 4 5 = ∣ ∣ ∣ − 3.2 + 2 5 ∣ ∣ ∣ ⇒ ∣ ∣ ∣ x − 1 3 ∣ ∣ ∣ + 4 5 = ∣ ∣ ∣ − 28 5 ∣ ∣ ∣ ⇒ ∣ ∣ ∣ x − 1 3 ∣ ∣ ∣ + 4 5 = 28 5 ⇒ ∣ ∣ ∣ x − 1 3 ∣ ∣ ∣ = 28 5 − 4 5 = 24 5 ⇒ x − 1 3 = ( ± 24 5 ) ⇒ ⎡ ⎢ ⎢ ⎣ x − 1 3 = 24 5 x − 1 3 = − 24 5 ⇒ ⎡ ⎢ ⎢ ⎣ x = 24 5 + 1 3 x = − 24 5 + 1 3 ⇒ ⎡ ⎢ ⎢ ⎣ x = 77 15 x = − 67 15
