\(\dfrac{2x+3}{0,5}=\dfrac{2x^2}{3x}\)
\(\Leftrightarrow3x\left(2x+3\right)=2x^2.0,5\)
\(\Leftrightarrow6x^2+9x=2x^2\)
\(\Leftrightarrow6x^2+9x-2x^2=0\)
\(\Leftrightarrow4x^2+9x=0\)
\(\Leftrightarrow x\left(4x+9\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\left(loại\right)\\x=-\dfrac{9}{4}\end{matrix}\right.\)
\(\dfrac{2x+3}{0,5}=\dfrac{2x^2}{3x}\Leftrightarrow3x\left(2x+3\right)=0,5.2x^2\)
\(\Leftrightarrow6x^2+9x=x^2\Leftrightarrow6x^2+9x-x^2=0\)
\(\Leftrightarrow5x^2+9x=0\Leftrightarrow x\left(5x+9\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\left(loại\right)\\5x+9=0\end{matrix}\right.\Leftrightarrow5x+9=0\Leftrightarrow x=\dfrac{-9}{5}\)
