Question

Tìm x biết:

a) | x+1,5 |= 2

b) \(\frac{2}{5}\)+| x+1 |=\(\frac{3}{4}\)

c) \(\frac{4}{5}\)-| x-\(\frac{1}{6}\) |=\(\frac{2}{3}\)

d) | x-\(\frac{2}{3}\) |+\(\frac{5}{4}\)=0

Làm giúp mk vs mk đang cần gấp nha!

Answer 1

a)

Th1

x+1,5=-2

x=-2- 1,5

x=3,5

Th2

X+ 1,5=2

X=2-1,5

X=1,5

Answer 2

\(|x+1,5|=2\)

\(|x+\frac{3}{2}|=2\)

\(\Rightarrow\left[{}\begin{matrix}x+\frac{3}{2}=2\\x+\frac{3}{2}=-2\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=2-\frac{3}{2}\\x=-2-\frac{3}{2}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\frac{1}{2}\\x=\frac{-7}{2}\end{matrix}\right.\)

Vậy \(x=\left[{}\begin{matrix}\frac{1}{2}\\\frac{-7}{2}\end{matrix}\right.\)