Question

Tìm x, biết
a. x + \(\dfrac{3}{10}=\dfrac{-2}{15}\)
b. \(\dfrac{-11}{12}x+0,25=\dfrac{5}{6}\)
c. x + (x+1)+(x+2)+........................+(x+2002)=2004

Answer 1

a. \(x=\dfrac{-2}{15}-\dfrac{3}{10}\)

\(x=\dfrac{-13}{30}\)

b. \(\dfrac{-11}{12}x+\dfrac{1}{4}=\dfrac{5}{6}\)

\(\dfrac{-11}{12}x=\dfrac{5}{6}-\dfrac{1}{4}\)

\(\dfrac{-11}{12}x=\dfrac{7}{12}\)

\(x=\dfrac{7}{12}:\dfrac{-11}{12}\)

\(x=\dfrac{-7}{11}\)

Answer 2

c:=>2003x+2005003=2004

=>2003x=-2002999

hay \(x\in\varnothing\)