Question

Tìm \(x\), biết :

a) \(\left(2x-3\right)-\left(x-5\right)=\left(x+2\right)-\left(x-1\right)\)

b) \(2\left(x-1\right)-5\left(x+2\right)=-10\)

Answer 1

a) (2x - 3) - (x - 5) = (x + 2) - (x - 1)

2x - 3 - x + 5 = x + 2 - x + 1

x + 2 = 3

x = 3 - 2

x = 1

b) 2(x - 1) - 5 (x + 2) = - 10

2x - 2 - 5x - 10 = -10

2x - 5x = -10 + 10 + 2

-3x = 2

x = -2/3

Answer 2

(2x-3)- (x-5)=(x+2)-(x-1)

=2x-3-x+5=x+2-x+1

=x+2=

x=3-2

x=1

b,2(x-1)-5(x+2)=-10

=2x-2-5x-10=-10

=2x-5x=-10+10+2

=-3x=2

x=\(\dfrac{2}{3}\)

Answer 3

Tìm x, biết:

a) (2x – 3) – (x – 5) = (x + 2) – (x – 1).

b) 2(x – 1) – 5(x + 2) = -10

Hướng dẫn làm bài:

a) (2x – 3) – (x – 5) = (x + 2) – (x – 1).

2x - 3 - x + 5 = x +2 - x +1

x +2 =3

x = 3 - 2

x = 1

Vậy x = 1

b) 2(x – 1) – 5(x + 2) = -10

2x - 2 - 5x -10 = -10

2x - 5x = -10 + 10 + 2

-3x = 2

x = \(\dfrac{-2}{3}\)

Vậy x=\(\dfrac{-2}{3}\)

Answer 4

( 2x - 3 ) - ( x - 5 ) = ( x +2 ) - ( x - 1 )

=> 2x - 3 -x + 5 = x + 2 - x + 1

=> 2x - x - x + x = 2 + 1 + 3 - 5

=> x = 6 -5

x = 1

b) \(2\left(x-1\right)-5\left(x+2\right)=-10\)

2x - 2 - 5x- 10 = -10

2x - 5x = -10 + 10 +2

-3x = 2

x = \(\frac{-2}{3}\)