Giải:
a) Xét các trường hợp:
TH1:
\(\left\{{}\begin{matrix}2x-y>0\\3-x>0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x>\dfrac{y}{2}\\x>3\end{matrix}\right.\)
TH2:
\(\left\{{}\begin{matrix}2x-y< 0\\3-x< 0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x< \dfrac{y}{2}\\x< 3\end{matrix}\right.\)
Vậy ...
b) Xét các trường hợp:
TH1:
\(\left\{{}\begin{matrix}x-2>0\\4-3x< 0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x>2\\x< \dfrac{4}{3}\end{matrix}\right.\Leftrightarrow2< x< \dfrac{4}{3}\Leftrightarrow x\in\varnothing\)
TH2:
\(\left\{{}\begin{matrix}x-2< 0\\4-3x>0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x< 2\\x>\dfrac{4}{3}\end{matrix}\right.\Leftrightarrow2>x>\dfrac{4}{3}\Leftrightarrow x=1\)
Vậy \(x=1\).
Chúc bạn học tốt!
