Question

Tìm x, biết:

5x (3 - 2x) = 2x - 3

Answer 1

\(5x\left(3-2x\right)=2x-3\)

\(5x\left(3-2x\right)-\left(2x-3\right)=0\)

\(5x\left(3-2x\right)+\left(3-2x\right)=0\)

\(\left(3-2x\right)\left(5x+1\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}3-2x=0\\5x+1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{1}{5}\end{matrix}\right.\)

Vậy........

Answer 2

\(5x\left(3-2x\right)=2x-3\\ \Leftrightarrow5x\left(3-2x\right)-\left(2x-3\right)=0\\ \Leftrightarrow5x\left(3-2x\right)+\left(3-2x\right)=0\\ \Leftrightarrow\left(3-2x\right)\left(5x+1=0\right)\)

\(\Leftrightarrow\left[{}\begin{matrix}3-2x=0\\5x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{1}{5}\end{matrix}\right.\)

Vậy...