Ta có: \(\left|3x-4\right|\le3\) (1)
Vì \(\left|3x-4\right|\ge0\) (2)
nên từ (1) và (2) \(\Rightarrow0\le\left|3x-4\right|\le3\)
\(\Rightarrow \left|3x-4\right|\in\left\{0;1;2;3\right\}\)
\(\Rightarrow x\in\left\{\dfrac{4}{3};\dfrac{5}{3};2;\dfrac{7}{3}\right\}\)
Vậy \(x\in\left\{\dfrac{4}{3};\dfrac{5}{3};2;\dfrac{7}{3}\right\}.\)