\(3 . ( x - 1 ) - ( x + 1 ) = -1\)
\(\Rightarrow 3( x - 1 ) - x - 1 = -1\)
\(\Rightarrow ( 3x - x ) - ( 3 + 1 ) = -1\)
\(\Rightarrow 2x - 4 = -1\)
\(\Rightarrow2x = -1 + 4 \)
\(\Rightarrow 2x = 3\)
\(\Rightarrow x = \dfrac{3}{2} \)
Vậy \(x = \dfrac{3}{2} \)
\(3x-3-x-1=1\Leftrightarrow2x-4=1\Leftrightarrow x=\dfrac{5}{2}\)