Nhã Doanh
ngonhuminh
Mashiro Shiina
giúp vs
Xét \(x\ge5\)
PT\(\Leftrightarrow3\left(x+4\right)+x-5=10\)
\(\Leftrightarrow3x+12+x-5=10\)
\(\Leftrightarrow4x=3\)
\(\Leftrightarrow x=\dfrac{3}{4}\left(loai\right)\)
Xét \(-4\le x< 5\)
PT\(\Leftrightarrow3\left(x+4\right)+5-x=10\)
\(\Leftrightarrow3x+12+5-x=10\)
\(\Leftrightarrow2x=-7\)
\(\Leftrightarrow x=-\dfrac{7}{2}\left(tm\right)\)
Xét \(x< -4\)
PT\(\Leftrightarrow3\left(-x-4\right)+5-x=10\)
\(\Leftrightarrow-3x-12+5-x=10\)
\(\Leftrightarrow-4x=17\)
\(\Leftrightarrow x=-\dfrac{17}{4}\left(tm\right)\)
Vậy S={\(-\dfrac{7}{2};-\dfrac{17}{4}\)}
