Question

Tìm x biết: 3-16x^2=0

 

Answer 1

`3-16x^2=0`

`<=>(\sqrt3)^2-(4x)^2=0`

`<=>(\sqrt3+4x)(\sqrt3-4x)=0`

`<=> [(\sqrt3=-4x),(\sqrt3=4x):}`

`<=> [(x=-\sqrt3/4),(x=\sqrt3/4):}`

Vậy `S={\pm \sqrt3/4}`.

Answer 2

Ta có: \(3-16x^2=0\)

\(\Leftrightarrow16x^2=3\)

\(\Leftrightarrow x^2=\dfrac{3}{16}\)

hay \(x\in\left\{\dfrac{\sqrt{3}}{4};-\dfrac{\sqrt{3}}{4}\right\}\)