\(2x.\left(x-\frac{1}{7}\right)=0\\ \Rightarrow\left\{{}\begin{matrix}2x=0\\x-\frac{1}{7}=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0\\x=\frac{1}{7}\end{matrix}\right.\)
Vậy...
\(2x.\left(x-\frac{1}{7}\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2x=0\\x-\frac{1}{7}=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0:2\\x=0+\frac{1}{7}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=\frac{1}{7}\end{matrix}\right.\)
Vậy \(x\in\left\{0;\frac{1}{7}\right\}.\)
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