\(2x-x^3=0\)
⇔ \(x\left(2-x^2\right)=0\)
⇔ \(\left[{}\begin{matrix}x=0\\2-x^2=0\end{matrix}\right.\)
⇔ \(\left[{}\begin{matrix}x=0\\x^2=2\end{matrix}\right.\)
⇔\(\left[{}\begin{matrix}x=0\\x=\sqrt{2}\\x=-\sqrt{2}\end{matrix}\right.\)
\(2x-x^3=0\)
\(x\left(2-x^2\right)=0\)
\(x=0\) hoặc \(2-x^2=0\)
\(x=0\) hoặc \(x=\sqrt{2}\) hoặc \(x=-\sqrt{2}\)
Vậy.........
Nhớ tick cho mình nha!