\(|2x-4|+1=5\)
\(|2x-4|=5-1\)
\(|2x-4|=4\)
\(\Rightarrow2x-4=\pm4\)
\(\Rightarrow\left\{{}\begin{matrix}2x-4=4\\2x-4=-4\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}2x=8\\2x=0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=4\\x=0\end{matrix}\right.\)
Chúc các bạn học tốt !!!
( 2x-4 )+1=5
<->2x-4=5-1
<->2x-4=4
<->2x=8
<->x=4
\(\left|2x-4\right|+1=5\)
\(\Rightarrow\left|2x-4\right|=5-1\)
\(\Rightarrow\left|2x-4\right|=4\)
\(\Rightarrow\)\(\left[{}\begin{matrix}2x-4=4\\2x-4=-4\end{matrix}\right.\)
\(\Rightarrow\)\(\left[{}\begin{matrix}2x=4+4\\2x=-4+4\end{matrix}\right.\)
\(\Rightarrow\)\(\left[{}\begin{matrix}2x=8\\2x=0\end{matrix}\right.\)
\(\Rightarrow\)\(\left[{}\begin{matrix}x=4\\x=0\end{matrix}\right.\)
nguyễn ly
Tìm x:
\(\left|2x-4\right|+1=5\)
\(\Rightarrow\left|2x-4\right|=4\)
\(\Rightarrow\left[{}\begin{matrix}2x-4=4\\2x-4=-4\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=4+4\Rightarrow2x=8\Rightarrow x=\dfrac{8}{2}=4\\2x=\left(-4\right)+4\Rightarrow2x=0\Rightarrow x=0\end{matrix}\right.\)
Vậy x = 4 và x = 0